final project

#include <iostream.h>
#include<conio.h>
main()
{
clrscr();
int selection;
float price,money,addmoney,balance,result,total_mark;
cout<<"\*****HARGA PAKEJ*****";
cout<<"\n1.Pakej 1(kelas B2)";
cout<<"\nJumlah \t\tRm643.00";
cout<<"\nDeposit \t\tRm250.00";
cout<<"\n-*-*-*-*-*-*-*-*-*-*";
cout<<"\n2.Pakej 2(kelas B)";
cout<<"\nJumlah \t\tRm775.00";
cout<<"\nDeposit \t\tRm250.00";
cout<<"\n-*-*-*-*-*-*-*-*-*-*";
cout<<"\n3.Pakej 3(kelas D)";
cout<<"\nJumlah \t\tRm893.00";
cout<<"\nDeposit \t\tRm250.00";
cout<<"\n-*-*-*-*-*-*-*-*-*-*";
cout<<"\n4.Pakej 4(kelas B1)";
cout<<"\nJumlah \t\tRm773.00";
cout<<"\nDeposit \t\tRm250.00";
cout<<"\n-*-*-*-*-*-*-*-*-*-*";
cout<<"\n\nEnter your selection =  ";
cin>>selection;
cout<<"please enter your money = ";
cin>>money;
cout<<"\nEnter your result = ";
cin>>result;
cout<<"PASS or FAILED ";
cin>>"\n pass or failed";

switch (selection)
{
case 1:price = 643.00;cout<<"\n\n kelas B2.";break;
case 2:price = 775.00;cout<<"\n\n kelas B.";break;
case 3:price = 893.00;cout<<"\n\n kelas D.";break;
case 4:price = 773.00;cout<<"\n\n kelas B1.";break;
case 5:result = 40;cout<<"\n\n result.";break;
default:cout<<"\n\nINVALID selection";
}

if(money < price)
{
    balance = price - money;
    cout<<"\nPlease insert more money (RM"<<balance<<")= ";
    cin>>addmoney;

}else
{
    balance = money - price;
    cout<<"\nPlease take your balance (RM"<<balance<<")";
}
{
if(total_mark < result)
    cout<<"\nPlease insert your result ("<<result<<")";
}
return 0;
}

@cosmo...

dgn ita dgn mia... nak wat fop kononnye... tetapi hmmm... hasilnye x siap2 gak... pening2... miss ayuni tolong la...

nur syazhara amanda

my baby girl... cute x???

pening kepala...

duk umah ingatkan nak upgrade blog tp x reti gak nak wat... tulis kat kertas reti la tp bila pakai c++ terus blank situ... mcm mane nak wat ni...??? hmmm...

operators & expressions

• (++)  pre-increment  (++m)  increment  m  by 1,  then  the  new  value  of  m  in  the  expression  in  which  m  resides.
• (++)  post-inctement  (m++)  use  the  current  of  m  in  the  expression  in  which  m  resides,  then  increment  m  by 1.
• (--)  pre-decrement  (--n)  decrement  n  by  1,  then  use  the  new  value  of  n  in  the  expression  in  which  n  resides.
• (--)  post-decrement  (--n)  use  the  current  value  of  n  in  the  expression  in  which  n  resides,  then  decrement  n  by  1.

eg:  #include <iostream.h>
main( )
{
in + result, a,b, m, n, p, q, x, y,
result=0;
a=6;
b=7;
m=8;
n=9;
p=3;
q=2;
x=4;
y=5;
result=++a+--b*4<++m*--n+4//p+++q--*4>x++*y--+4;
cout<<"inresult"<<result;
return0;
{

output  result
=(1+6)+(7-1)*4<(1+8)*(9-1)+4     //         3+(2*4)>4*5+4
=7+24<72+4                                 //           3+8>20+4
=31<76                                        //            11>24
=true(1)                                  true(1)          false(0)

akhirnye  setelah  bnyk chapter yg kupelajari chapter ni yg paling ku fahami...
hehehe...
harap2  chapter  seterusnye  lebih  senang la...

baby new born